Question

L and M are mid points of two equal chords AB and CD of circle with centre O. prove that m angle OLM= m angle OML.​

Answer 1

Step-by-step explanation:

Join O to A, B, C, D.

now connect OL and OM

here,

∠OLB=90° = ∠OMD            (cente subtends 90° to a chord's midpoint)

AB*1/2=MD*1/2

LB=MD

OB=OD      (radius)

By RHS LOB≅MOD

hence LO=MO

⇒∠OLM=∠OML