l and m are two parallel lines interested by another pair of parallel lines p and q ( see Dig. 7.19)show that ABC= CDA.
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if the parallel m and p parallel q them angle ABC = angle CDA(alternative angles)
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Given : l and m are parallel lines intersected by another pair of parallel lines P and Q
To prove : triangle ABC is congruent to triangle CDA
Proof : In ΔABC and ΔCDA
∠BCA = ∠DAC (Alternate interior angles)
∠BAC = ∠DCA (Alternate interior angles)
AC = AC (common)
Therefore, By ASA congruence,
By ASA congruence,ΔABC ≅ ΔCDA
Proved
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