Question

l and M are two Parallel Lines intersected by another pair of parallel lines P and Q show that triangle ABC congruent to triangle CDA​

Answer 1

Answer:

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Answer 2

$\huge\mathfrak\pink{Answer}$

★ Given:-

P||Q & L||M

★ Prove:-

△ ABC ≅ △CDA

★ Proof:-

In △ ABC & CDA

∠ 1 = ∠2 (Alternate Angle)

∠2 = ∠4 ( Alternate Angle)

AC = AC (Common)

$\therefore$ △ABC ≅ △CDA (By AAS rule)