L'ART COMPOSITION 38 Message : 4 Marks Date : UNIT Assignment B.3 Name Section UNIT Class Roll No. : Shreya's mother Mrs Sen had the following conversation with Ms Renu, Shreya's school receptionist . Since Ms Renu was leaving for home early, she left a message for Shreya. Read the conversation below, and write the message and put it in a box. Mrs Sen : Good morning, could you please convey a message to Shreya Singh of Class 7th B ? Ms Renu : Yes, I'll convey the message. Mrs Sen Please tell Shreya that I will not be at home for lunch today. The house keys are with our tenant, Mrs Sunanda. She should take them from her and have her lunch, and not wait for me. Ms Renu : I'll just inform her. Mrs Sen : Thank you very much.
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Answer:
Here is the answer to questions like: What is the square root of 1336? | √1336 or what is the square root of 1336?
Use the square root calculator below to find the square root of any imaginary or real number. See also in this web page a Square Root Table from 1 to 100 as well as the Babylonian Method or Hero's Method.
The Babylonian Method also known as Hero's Method
See below how to calculate the square root of 1336 step-by-step using the Babylonian Method also known as Hero's Method.
In this case we are going to use the 'Babylonian Method' to get the square root of any positive number.
We must set an error for the final result. Say, smaller than 0.01. In other words we will try to find the square root value with at least 1 correct decimal places.
Step 1:
Divide the number (1336) by 2 to get the first guess for the square root .
First guess = 1336/2 = 668.
Step 2:
Divide 1336 by the previous result. d = 1336/668 = 2.
Average this value (d) with that of step 1: (2 + 668)/2 = 335 (new guess).
Error = new guess - previous value = 668 - 335 = 333.
333 > 0.01. As error > accuracy, we repeat this step again.
Step 3:
Divide 1336 by the previous result. d = 1336/335 = 3.9880597015.
Average this value (d) with that of step 2: (3.9880597015 + 335)/2 = 169.4940298508 (new guess).
Error = new guess - previous value = 335 - 169.4940298508 = 165.5059701492.
165.5059701492 > 0.01. As error > accuracy, we repeat this step again.
Step 4:
Divide 1336 by the previous result. d = 1336/169.4940298508 = 7.8822835304.
Average this value (d) with that of step 3: (7.8822835304 + 169.4940298508)/2 = 88.6881566906 (new guess).
Error = new guess - previous value = 169.4940298508 - 88.6881566906 = 80.8058731602.
80.8058731602 > 0.01. As error > accuracy, we repeat this step again.
Step 5:
Divide 1336 by the previous result. d = 1336/88.6881566906 = 15.0640181266.
Average this value (d) with that of step 4: (15.0640181266 + 88.6881566906)/2 = 51.8760874086 (new guess).
Error = new guess - previous value = 88.6881566906 - 51.8760874086 = 36.812069282.
36.812069282 > 0.01. As error > accuracy, we repeat this step again.
Step 6:
Divide 1336 by the previous result. d = 1336/51.8760874086 = 25.7536770165.
Average this value (d) with that of step 5: (25.7536770165 + 51.8760874086)/2 = 38.8148822126 (new guess).
Error = new guess - previous value = 51.8760874086 - 38.8148822126 = 13.061205196.
13.061205196 > 0.01. As error > accuracy, we repeat this step again.
Step 7:
Divide 1336 by the previous result. d = 1336/38.8148822126 = 34.419787562.
Average this value (d) with that of step 6: (34.419787562 + 38.8148822126)/2 = 36.6173348873 (new guess).
Error = new guess - previous value = 38.8148822126 - 36.6173348873 = 2.1975473253.
2.1975473253 > 0.01. As error > accuracy, we repeat this step again.
Step 8:
Divide 1336 by the previous result. d = 1336/36.6173348873 = 36.4854516068.
Average this value (d) with that of step 7: (36.4854516068 + 36.6173348873)/2 = 36.5513932471 (new guess).
Error = new guess - previous value = 36.6173348873 - 36.5513932471 = 0.0659416402.
0.0659416402 > 0.01. As error > accuracy, we repeat this step again.
Step 9:
Divide 1336 by the previous result. d = 1336/36.5513932471 = 36.551274283.
Average this value (d) with that of step 8: (36.551274283 + 36.5513932471)/2 = 36.5513337651 (new guess).
Error = new guess - previous value = 36.5513932471 - 36.5513337651 = 0.000059482.
0.000059482 <= 0.01. As error <= accuracy, we stop the iterations and use 36.5513337651 as the square root.
So, we can say that the square root of 1336 is 36.5513 with an error smaller than 0.01 (in fact the error is 0.000059482). this means that the first 4 decimal places are correct. Just to compare, the returned value by using the javascript function 'Math.sqrt(1336)' is 36.55133376499413.
Answer:
hope it will helpful for you