English, asked by shivasinghmohan629, 1 month ago

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Answered by Limafahar
2

1) solve the equations :-

\large\boxed{\textsf{\textbf{\red{Question\: A}}}}

a) \: 2y +  \frac{5}{2}  =  \frac{37}{2}  \\

ans) \: 2y +  \frac{5}{2 }  =  \frac{37}{2}

2y =  \frac{37}{2}  -  \frac{5}{2}

2y =  \frac{37 - 5}{2}

2y =  \frac{32}{2}

2y = 16

y =  \frac{16}{2}

y = 8

\large\boxed{\textsf{\textbf{\red{Question\:B}}}}

b) \: 5t + 28 = 10 \\

ans) \: 5t + 28 = 10

5t = 10 - 28

5t =  - 28 + 10

5t =  - (28 - 10)

5t =  - 18

t =  \frac{ - 18}{5}

\large\boxed{\textsf{\textbf{\red{Question\:C}}}}

c) \:  \frac{a}{5}  +  3 = 2 \\

ans)  \: \frac{a}{5}  + 3 = 2

 \frac{a}{5}  = 2 - 3

 \frac{a}{5}  =  - 3 + 2

 \frac{a}{5}  =  - (3 - 2)

 \frac{a}{5}  =  - 1

a =  - 1 \times 5

a =  - 5

\large\boxed{\textsf{\textbf{\red{Question\:D}}}}

d) \:  \frac{q}{4}  + 7 = 5 \\

ans) \:  \frac{q}{4}  + 7 = 5

 \frac{q}{4}  = 5 - 7

 \frac{q}{4}  =  - 2

q =  - 2 \times 4

q =  - 8

\large\boxed{\textsf{\textbf{\red{Question\:E}}}}

e) \:  \frac{5}{2} x = -  10 \\

ans) \:  \frac{5}{2} x =  - 10

x =  - 10 \times 2

5x =  - 20

x =  \frac{ - 20}{5}

x =  - 4

\large\boxed{\textsf{\textbf{\red{Question\:F}}}}

f) \:  \frac{5}{2} x =  \frac{25}{4} \\

ans) \:  \frac{5}{2} x =  \frac{25}{4}

5x =  \frac{25}{4}  \times 2

5x =  \frac{25}{2}

x =  \frac{25}{2}  \times  \frac{1}{5}

x =  \frac{5}{2}

\large\boxed{\textsf{\textbf{\red{Question\:G}}}}

g) \: 7m +  \frac{19}{2}  = 13 \\

ans) \: 7m +  \frac{19}{2}  = 13

7m = 13 -  \frac{19}{2}

7m =  \frac{13 \times 2 - 19}{2}

7m =  \frac{26 - 19}{2}

m =  \frac{7}{2}

m =  \frac{7}{2}  \times  \frac{1}{7}

m =  \frac{1}{2}

\large\boxed{\textsf{\textbf{\red{Question\:H}}}}

h) \: 6z + 10 =  - 2 \\

ans) \: 6z + 10 =  - 2

6z =  - 2 - 10

6z =  - (2  +  10)

6z =  - 12

z =  \frac{ - 12}{6}  =  - 2

\large\boxed{\textsf{\textbf{\red{Question\:i}}}}

i) \:  \frac{3l}{2}  =  \frac{2}{3} \\

ans) \frac{3l}{2}  =  \frac{2}{3}

3l =  \frac{2}{3}  \times 2

3l =  \frac{4}{3}

l =  \frac{4}{3}  \times  \frac{1}{3}  =  \frac{4}{9}

\large\boxed{\textsf{\textbf{\red{Question\:J}}}}

j) \:  \frac{2b}{ 3} - 5 = 3 \\

ans) \:  \frac{2b}{3}  - 5 = 3

 \frac{2b}{3}  = 3 + 5

 \frac{2b}{3}  = 8

2b = 8 \times 4 = 24

b =  \frac{24}{2}  = 12

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