Math, asked by krishankumarjha33, 10 days ago

L. C. M of 24,28,32,14,12​

Answers

Answered by VishalRai46
5

Step-by-step explanation:

Write your numbers in the top row.

Divide your numbers by prime numbers as long as at least one of your numbers is evenly divisible by a prime number.

Division Table

2 12,14,24,28,32

2 6, 7, 12, 14, 16

2 3, 7, 6, 7, 8

2 3, 7, 3, 7, 4

2 3, 7, 3, 7, 2

3 3, 7, 3, 7, 1

7 1, 7, 1, 7, 1

1 1, 1, 1, 1 1

Bring down any numbers that are not evenly divisible by the prime number.

When the last row of results is all 1's you are done.

Find the product of the prime numbers in the first column to get the LCM:

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 7

LCM = 672

Therefore,

LCM(12, 14, 24, 28, 32) = 672

Answered by XtarLie
4

Answer:

Arrange the Inputs 24,28,32,14,12 in a horizontal line separated by commas and divide them with a prime number. Note the quotients in the next row and divide with quotients with prime numbers again. Continue the process until you have all co primes in the last.

2 24, 28, 32, 14, 12

2 12, 14, 16, 7, 6

2 3, 7, 8, 7, 6

3 3, 7, 4, 7, 3

7 1, 7, 4, 7, 1

1, 1, 4, 1, 1

As all the numbers left in the last row are co primes you need not do the common division process further.

To obtain the Least Common Multiple, multiply the prime numbers with which you have divided the given numbers and the co primes in the last row i.e. 2 x 2 x 2 x 3 x 7 x 1 x 1 x 4 x 1 x 1 = 672

Therefore, LCM of 24,28,32,14,12 is 672

Similar questions