Question

L.C.M. of 56 72
= 3x5x7x11 - 1155
Product of L.C.M. and H.C. - 1155 x 15
= (157)x165 = (105)x(165) - Product of given numbers.
Exercise
For each of the following pairs of numbers, show that the product of their
their product:
(i) 56,72
(ii) 45, 105
(iii) 117, 221​

Answer 1

Step-by-step explanation:

LCM of 1155 and 1365 is LCM = 31. 51. 71. 111. 131 = 15015

HCF of 1155 and 1365 is GCF = 31. 51. 71 = 105

LCM * HCF =15015*105=1576575

1155*1365=1576575

Answer 2

Answer:

L.C.M. of 56 and 72 is-

=3×5×7×11-1155

Product of L.C.M.and H.C. - 1155×15

=(157)×165=(105)×(165) - Product of given numbers.

For each of the following pairs of numbers,

show that the product of their products