Math, asked by januchin, 1 year ago

L.C.M of the numbers 2*2*2*2*2*2*2*3*3*3*3*7,2*2*2*3*3*3*3*11

Answers

Answered by Gomisan
4
1st number=2^7*3^4*7=72576
2nd number=2^3*3^4*11=7128
Required L.C.M=Product of highest powers of each number.
=2^7*3^4*7*11=798336
Ans:The required L.C.M. is 798336.

Answered by bhaghi
2
2×2×2×2×2×2×2×3×3×3×3×7 = 2⁷×3⁴×7
2×2×2×3×3×3×3×11 = 2³×3⁴×11
LCM = 2⁷×3⁴×7×11
        = 128×81×77
        = 10368×77
        = 798336
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