Question

L.C.M. of two numbers is 120 and their H.C.F is 10 which of the following can be the sum of those two numbers ?

Answer 1

 the product of two numbers = LCM * HCF
Let the required numbers be  10a and 10b
 10a × 10b = 1200
 ab = 12
co-primes with sum 12 are (3,4), (2,6), (1,12) i.e  (30, 40), (20, 60), (10, 120)
 Possible numbers are (30, 40) and (10, 120) 

Answer 2

Hello friends,
L.C.M 120 ,,,,, H.C.F 10
120 / 10 = 12. then ,
12=3×4 | the 3&4 are factors of 12
First number = 4×10 = 40
Second number = 120×3 = 360

1) 40
2) 360