L.C.M. of two numbers is 120 and their H.C.F is 10 which of the following can be the sum of those two numbers ?
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5
the product of two numbers = LCM * HCF
Let the required numbers be 10a and 10b
10a × 10b = 1200
ab = 12
co-primes with sum 12 are (3,4), (2,6), (1,12) i.e (30, 40), (20, 60), (10, 120)
Possible numbers are (30, 40) and (10, 120)
Let the required numbers be 10a and 10b
10a × 10b = 1200
ab = 12
co-primes with sum 12 are (3,4), (2,6), (1,12) i.e (30, 40), (20, 60), (10, 120)
Possible numbers are (30, 40) and (10, 120)
Answered by
0
Hello friends,
L.C.M 120 ,,,,, H.C.F 10
120 / 10 = 12. then ,
12=3×4 | the 3&4 are factors of 12
First number = 4×10 = 40
Second number = 120×3 = 360
1) 40
2) 360
L.C.M 120 ,,,,, H.C.F 10
120 / 10 = 12. then ,
12=3×4 | the 3&4 are factors of 12
First number = 4×10 = 40
Second number = 120×3 = 360
1) 40
2) 360
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