L.C.M of two numbers is 2079 and H.C.F is 27. If one number is 297.find the other numbers .PLEASE give me full proper procedure solution of this question.?
Anonymous:
189
Answers
Answered by
2
LCM (a,b)×HCF (a,b)=a×b
2079×27=297×b
b=(2079×27)÷297
b=189
Thank you
2079×27=297×b
b=(2079×27)÷297
b=189
Thank you
THANKYOU
Answered by
1
L.C.M. of two numbers is 2079
H.C.F. of two numbers is 27
One no. is 297
Other no. is ?
Let the other no. be b
L.C.M.(a*b)*H.C.F.(a*b)= a* b
2079*27=297*b
56133= 297* b
56133/297 = b
189= b
So the other no. is 189
H.C.F. of two numbers is 27
One no. is 297
Other no. is ?
Let the other no. be b
L.C.M.(a*b)*H.C.F.(a*b)= a* b
2079*27=297*b
56133= 297* b
56133/297 = b
189= b
So the other no. is 189
Similar questions