Math, asked by ajitnanda02, 1 day ago

L.C.M. of two prime numbers X and Y (x>y) is 161. The value of 3y-x is:​

Answers

Answered by mahanteshgejji
1

Answer:

3y - x = - 2

Step-by-step explanation:

LCM of prime numbers is product of those two numbers.

xy = 161

xy = 23 x 7

Since x > 7

x = 23 and y = 7

∴ 3y - x = 3 (7) - 23

= 21 - 23

= - 2

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