L.C.M. of two prime numbers x and y (x>y) is 161. the value of 3y_x is
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LCM of two prime numbers x and y = 161
LCM of the prime number is their product
Therefore x × y =161
x × y = 23 × 7 where x > y
x = 23 and y = 7
Now
3y-x
= 3(7)-23
=21-23
=-2
LCM of the prime number is their product
Therefore x × y =161
x × y = 23 × 7 where x > y
x = 23 and y = 7
Now
3y-x
= 3(7)-23
=21-23
=-2
Answered by
3
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