Question

L.C.M of x-2 and x2 +x-6 is

Answer 1

Answer:

first let us factorise

${x}^{2} + x - 6$

=

$x ^{2} + 3x - 2x - 6$

=x(x+3)-2(x+3)

=(x-2)(x+3)

NOW LCM OF X-2 AND

$x ^{2} + x - 6$

Is (x-2)(x+3)

=x^2+x+6