Question

l
For the one-dimensional motion of a particle
described by position x = t + cos t (where t is time in
s and x is in m), the velocity of particle is zero at time
t equals to
(1) 0.3 s
(2) 1 s
(3) 0.2s
(4) 1.57 s


pls answer step wise...
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Answer 1

Answer:

4. 1.57

Explanation:

Given x=t+cost

v=dx/dt=1-sint

now

v=0

1-sint=0

sint=1

t=π/2

t=1.57s

Answer 2

Answer:

Given x=t+cost

v=dx/dt=1-sint

now

v=0

1-sint=0

sint=1

t=π/2

t=1.57s

Explanation: