Question

(L) going abroad for quite
1
sometime.
1
(g) This paper
(appear) twice a week.​

Answer 1

Answer:

1High concentration of electronegative/electropositive elements available in the atmosphere/environment (to allow basic chemical reactions that life may need: on earth, life adapted for oxygen);

1High concentration of electronegative/electropositive elements available in the atmosphere/environment (to allow basic chemical reactions that life may need: on earth, life adapted for oxygen);2Low and stable income of radiation (because radiation disrupts complex molecules much faster than life could or would bear);

1High concentration of electronegative/electropositive elements available in the atmosphere/environment (to allow basic chemical reactions that life may need: on earth, life adapted for oxygen);2Low and stable income of radiation (because radiation disrupts complex molecules much faster than life could or would bear);3Enough distance from the sun so as to not be highly influenced by solar flares (also because of radiation). Though red dwarves last for much longer than K-type stars such as our sun, it’s debatable if earth-like lifeforms would be able to live in a red dwarf system, because the habitable zone around that kind of star is simply too close and the planet would suffer a lot in the early ages with solar flares, let alone keep an atmosphere;

1High concentration of electronegative/electropositive elements available in the atmosphere/environment (to allow basic chemical reactions that life may need: on earth, life adapted for oxygen);2Low and stable income of radiation (because radiation disrupts complex molecules much faster than life could or would bear);3Enough distance from the sun so as to not be highly influenced by solar flares (also because of radiation). Though red dwarves last for much longer than K-type stars such as our sun, it’s debatable if earth-like lifeforms would be able to live in a red dwarf system, because the habitable zone around that kind of star is simply too close and the planet would suffer a lot in the early ages with solar flares, let alone keep an atmosphere;4Some kind of protection against “fast-events” (fast-events being defined as those that change conditions faster than life can adapt to them: meteor strikes, planetary collisions, gamma ray bursts, solar flares, etc.)

Answer 2

Answer:

Question:-

Find the length of a side of an equilateral triangle perimeter is 72 cm.

Given :-

Figure is equilateral triangle

Perimeter of figure = 72cm

Aim :-

To find side of the triangle

Equilateral triangle:-

In a equilateral triangle, all the sides are equal

All angles are equal.

Hence, Perimeter = Side + side + side => 3 × side

Let the side be x cm.

As we know that,

3 × side = Perimeter,

substituting the values,

3 × x = 72

Transposing 3 to the RHS (Right hand side),

x = \dfrac{72}{3}x=

3

72

By reducing to the lowest terms,

x = 24

Side of the triangle = 24cm