Question

L.H.S. = x2 – y2
= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2
= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)
= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – – tan2 θ = 1
= R.H.S.hii
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Answer 1

Answer:

L.H.S. = x2 – y2

= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2

= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)

= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – – tan2 θ = 1