Question

(l+i) is a root of real quadratic equation x^2+px+q=0 then p+q=?

Answer 1

Answer:

Given equation

x

2

+px+q

Also, given p,q are the roots of the equation.

p+q=−p

2p=−q .....(1)

And pq=q

q(p−1)=0

⇒q=0 or p=1

So, by (1), q=0⇒p=0

Hence, the values of p are 0,1.

Step-by-step explanation:

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