Question

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If α and β are the zeros of the polynomial x2−6x+2 , then (1α+1β)=​

Answer 1

Answer:

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Answer 2

Answer:

${x}^{2} + 6x + 2 = 0 \\ \alpha + \beta = \frac{ - b}{a} \\ = \frac{ - 6}{1} \\ = - 6 \\ \\ \alpha \times \beta = \frac{c}{a} \\ = \frac{2}{1} \\ = 2 \\ required \: sum = \frac{ \alpha + \beta }{ \alpha \times \beta }=\frac{ - 6}{2} \\ = - 3$