लोकोमोटिव फुल सा ट्रेन ऑफ मास 20 किलो न्यूटन फर्स्ट लॉ ऑफ 1 रेशों एंड विद वेलोसिटी ऑफ 3 किलोमीटर पर आवर फाइंड द पावर ऑफ इंजीनियर फ्रिक्शन रेजिस्टविटी न्यूटन पर किलोमीटर
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Answer:
The acceleration w is obtained by differentiating v with respect to time.
w=
dt
dv
=
2
s
a
dt
ds
=
2
s
a
a
s
=
2
a
2
(As locomotive is in unidirectional motion)
Hence force acting on the locomotive F=mw=
2
ma
2
Let, v=0 at t=0 then the distance covered during the first t seconds
s=
2
1
wt
2
=
2
1
2
a
2
t
2
=
4
a
2
t
2
Hence the work, W=Fs=
2
ma
2
4
(a
2
t
2
)
=
8
ma
4
t
2
So, x=8
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