Question

लोकोमोटिव फुल सा ट्रेन ऑफ मास 20 किलो न्यूटन फर्स्ट लॉ ऑफ 1 रेशों एंड विद वेलोसिटी ऑफ 3 किलोमीटर पर आवर फाइंड द पावर ऑफ इंजीनियर फ्रिक्शन रेजिस्टविटी न्यूटन पर किलोमीटर​

Answer 1

Answer:

The acceleration w is obtained by differentiating v with respect to time.

w=

dt

dv

=

2

s

a

dt

ds

=

2

s

a

a

s

=

2

a

2

(As locomotive is in unidirectional motion)

Hence force acting on the locomotive F=mw=

2

ma

2

Let, v=0 at t=0 then the distance covered during the first t seconds

s=

2

1

wt

2

=

2

1

2

a

2

t

2

=

4

a

2

t

2

Hence the work, W=Fs=

2

ma

2

4

(a

2

t

2

)

=

8

ma

4

t

2

So, x=8