लेखक डाँडे के ऊपर कितनी ऊँचाई पर था।
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Acceleration due to gravity at poles = 9.8m/s
2
The apparent acceleration due to gravity at a height h is given by g
′
=g(1−2h/R).
Rearranging the terms, we get, (g
′
−g)/g=2h/R⟹h=(R/2)(δg/g)=(6400/2)×(1/100)=32km.
The correct option is (a)
Acceleration due to gravity at poles = 9.8m/s
2
The apparent acceleration due to gravity at a height h is given by g
′
=g(1−2h/R).
Rearranging the terms, we get, (g
′
−g)/g=2h/R⟹h=(R/2)(δg/g)=(6400/2)×(1/100)=32km.
The correct option is (a)
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