Question

L length of rectangle is 72 and perimeter is 236 what is the breadth of rectangle

Answer 1

Given:

• Length=72 cm
• Perimeter=236 cm

To find:

• Breadth

Solution:

${\boxed{\pink{\bf{perimeter \: of \: rectangle \: = 2(l + b) }}}} \\ 2(72 + b) = p \\ 144 + 2b = 236 \\ 2b = 236 - 144 \\ 2b = 92 \\ b = \frac{92}{2} \\ b = 46 \\ \\ \\ \fbox \orange{verification } \\ p = 2(l + b) \\ p = 2(72 + 46) \\p = 114 + 92 \\ p = 236 \\ 236 = 236 \\ \\ LHS = RHS \:$