Question

l length of the fence of a Trapezium shaped will ABCD is 120 M is bc =48 m cd = 17 M and ad= 40 m ,find the area of this field .Side ab is perpendicular to the parallel side ad and bc

Answer 1

Solution;
Given:

Length of the fence of a trapezium ABCD =120 m. BC = 48 m, CD = 17 m and AD = 40 m,

Length of the fence of a trapezium ABCD =AB +BC+ CD+ AD
120=AB + 48+17+40
120 = AB + 105
120 – 105 = AB
AB= 15 m
Height (AB) = 15 m

Area of Trapezium
= 1/2 x sum of parallel sides x perpendicular distance

Area of Trapezium
= (1/2) (48+40) 15
= ½(88)(15)
= 44× 15
=660 m²
Hence, the area of the field = 660 m²
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Hope this will help you...

Answer 2

Answer:

Given: BC = 48 m, CD = 17 m, AD = 40 m and perimeter = 120 m

Perimeter of trapezium ABCD = AB + BC + CD + DA

120 = AB + 48 + 17 + 40

120 = AB = 105

AB = 120 105 = 15 m

Area of the field = *(BC + AD)x AB 2

(48+ 40)x15 = , = 660 m2 x 88×15

Hence, area of the field ABCD is 660 m2.

hope this help you