(l + m)2 – (l-m)2 factorise
help me to clear this
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Step-by-step explanation:
applying formulae a²-b²= (a+b) (a-b)
= {(l+m)+(l-m)} {(l+m)-(l-m)}
= (l+m+l-m)(l+m-l+m)
(+m) and (-m) will cut and similarly (+l) and(-l) will cut
= 2l ×2m
= taking 2 common , 2lm (Ans)
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