(l+m)²-(l-m)² factorize
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Using the identity a2 - b2 = (a+b)(a-b), we have
(l + m)2 - (l-m)2 = [(l + m) + (l -m)][(l + m) - (l - m)]
= [l + m + l - m][l + m - l + m]
= (2l)(2m) = 2cross times 2(l × m)
= 4lm
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