Question

l║m ∠3=x+30°and angle 6=2x+15°find ∠1 and ∠8

Answer 1

Answer:

angle1=75° angle8=105°

Step-by-step explanation:

angle3+angle6=180°(sum of internal angles)

3x+45°=180°

3x=135°

x=45°

angle3=45+30=75°

angle1=angle3(vertically opposite angle)

angle1=75°

angle6=2×45°+15°=105°

angle6=angle8(vertically opposite angle)

angle8=105°

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Answer 2

Answer:

75° and 105°

Step-by-step explanation:

∠3 and ∠6 are consecutive interior angels and supplementary angels

(x + 30)° + (2x + 15)° = 180°

3x + 45 = 180

3x = 180 - 45

3x = 135

x = 45°

∠3 ≅ ∠1 (as verticals) ===> m∠1 = 45° + 30° = 75°

∠8 ≅ ∠6 (as verticals) ===> m∠8 = 90° + 15° = 105°