l, m and n are three parallel lines intersected by transversal p and q such that l, m and n cut equal intercepts ab and bc on p. show that l, m and n cuts off equal intercepts de and ef on q also
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Let l, m and n be three parallel lines intersected by two transversals p and q such that l, m and n cut off equal intercepts AB and BC on p i.e. AB = BC.
To show: l, m and n cut off equal intercepts DE and EF on q also, i.e. DE = EF.
Construction: Join AF intersecting m at G.
So, the trapezium ACFD is divided into two triangles: ΔACF and ΔAFD.
It is given that AB = BC
⇒ B is the mid point of AC
Now in ΔACF, B is the mid point of AC and BG || CF (as m || n )
∴ By mid point theorem, G is the mid point of AF.
Now in ΔAFD, G is the mid point of AF and GE || AD (as l || m)
⇒ E is the mid point of DF (by mid point theorem)
⇒ DE = EF
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example no.3
hope it helps
hope it helps
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