Math, asked by rajnithakre08, 9 months ago

(l-m) (m-n) +(m-n) (n-l) -(n-l)(l-m) ​

Answers

Answered by patelrekha0829
1

Answer:

(l-m)(l-m)+(m-n)(n-l)-(n-l)(l-m)

l(m-n)-m(m-n)+m(n-l)-n(n-l)-n(n-l)-n(l-m)-l(l-m)

lm-ln-m^-mn+mn-ml-n^-nl-nl-nm-l^-lm

ln-m^-n^-nl-nl-nm-l^-lm

this is your answer.....

hope it helps you...

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