Question

(l+m) whole square - 4lm​

Answer 1

(l+m)²-4lm
l²+m²+2lm-4lm
l²+m²-2lm
(l-m)²
here is your answer

Answer 2

$<h2 > heya$



$<h3 > answer....$



To factorise




$(l + m) {}^{2} - 4lm$




Extending it we get ...




$l {}^{2} + m {}^{2} + 2lm - 4lm$




$l {}^{2} + m {}^{2} - 2lm$




$(l - b) {}^{2}$




$(l - b)(l - b)$





Hope it helps you




$<marquee > prabhudutt$





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