Question

l need to know the answer quickly
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Answer 1

Answer:

send it again

Step-by-step explanation:

ok.......

Answer 2

Answer:

$(1) \frac{sin(c - a) }{sinc \: sina} + \frac{sin(b - a)}{sina \: sinb} + \frac{sin(c - b)}{sinb \: sinc} \\ first \: term \: \\ \frac{sin(c - a)}{sinc \: sina} = \frac{sinc \: cosa - cosc \: sina}{sinc \: sina} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = cota - cotc \\ \\ Like \: this \:, we \: can \: write \: second \: and \: third \\ term \\second \: term = cotb - cota \\ third \: term = cotc - cotb \: \: \\ On \: adding \: we \: get \: \\ \frac{sin(c - a)}{sina \: sinc} + \frac{sin(b - a)}{sinb \: sina} + \frac{sin(c - b)}{sinb \: sinc } = 0 \\ \\ hope \: it \: will \: help \: you...$