L parllal M and P parpendicular L and q parpendicular M show that p parllal q reason of your answer
Attachments:
Answers
Answered by
4
given:
=>L||M
=>p perpendicular to L
=>q perpendicular to M
to prove: p||q
proof:-
since, L||M
so, angle MBC=angleLCq=90°
coz,they are corresponding angles.
since,angle LCq=angle LDp
both are 90°
and they are co-interior angle.
this is only possible when p||q
so,p||q
Hence proved...
@Altaf
=>L||M
=>p perpendicular to L
=>q perpendicular to M
to prove: p||q
proof:-
since, L||M
so, angle MBC=angleLCq=90°
coz,they are corresponding angles.
since,angle LCq=angle LDp
both are 90°
and they are co-interior angle.
this is only possible when p||q
so,p||q
Hence proved...
@Altaf
ALTAF11:
my pleasure!!!
Answered by
1
Angle PDC =angle DAB (corresponding angles)
90° = angle DAB
Angle DAB + Angle ABC
90° + 90° = 180°
Hence,p//q as the sum of interior angles is 180°.
90° = angle DAB
Angle DAB + Angle ABC
90° + 90° = 180°
Hence,p//q as the sum of interior angles is 180°.
Similar questions