Question

L QRP=90,L PQR=45 find x+y+z​

Answer 1

Answer:

Since PBCR becomes rectangle

∴ PB=RC=x

⇒AP=x

If QC=RC=x ∴∠CRQ=∠RCQ=45^{0}45

0

Since ∠PRC=90^{0}90

0

∴∠PRQ=45^{0}45

0

and sum of angles a triangle is 180^{0}180

0

∴∠PQR=90^{0}90

0

and ∠PRQ=45^{0}45

0

∴∠QPR=180^{0}180

0

-(90^{0}90

0

+45^{0}45

0

)=45^{0}45

0