Question

l Surace area of the cone.
A conical tent is 10 m high and the radius of its base is 24 m. Find
(i) slant height of the tent.
(ii) cost of the canvas required to make the tent, if the cost of 1 m canvas is Rs 70.​

Answer 1

Given:

• Height of the conical tent = 10m

• Radius of its base = 24m.

To find :

• Slant height

• Cost of the canvas required to make the tent, if the cost of 1m² canvas is RS 70.

Solution :

i) As we know that :

$\star \boxed{ \bold{ l = \sqrt{ {r}^{2} + {h}^{2} }}}$

Here , l is slant height

$\implies \: l = \sqrt{ {24}^{2} + {10}^{2} } \\ \\ \implies \: l = \sqrt{576 + 100} \\ \\ \implies \: l = \sqrt{676} \\ \\ \implies \: l = 26m$

Hence ,the slant height is 26 m .

Now,

ii) Here , we have to find curved surface area :

$\star \boxed{\bold{curved \: surface \: area \: of \: cone = \pi \: r \: l}}$

=> CSA of tent = 22/7 (24)(26)

=> CSA of tent = 13728/7. m²

Now , cost :

• cost of 1m² canvas is RS 70

cost of 13738/7 m²

=> 13728/7× 70

=> 137280

Hence ,the cost is RS 137280

Answer 2

Answer:

$\huge \pink \star{ \green{ \boxed{ \boxed{ \boxed{ \purple{ \mathfrak{Answer}}}}}}} \pink\star</p><p>$

Height,h=10 m

Radius,r=24 m

Let the slant height be l. Then,

$= > l ^{2} = {r}^{2} + {h}^{2}$

$= > l ^{2} = 676$

$= > l = 26m$

Therefore, the slant height of the tent is $\huge\boxed{26 m}$

Now,

CSA of tent =

$\pi \: rl = \frac{22}{7} \times 24 \times 26 = \frac{13728}{7} {m}^{2}$

Hence, cost of canvas =

$\frac{13728}{7} \times 70 = 137280$Rs.