L [ t ^ { 3 } e ^ { - 2 t } ]
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Answer:
Given L[(t^3)e^(-2t)]
Step-by-step explanation:
USING FORMULA
L((t^(n))*e^as) =n!/(s+a)^(n+1)
so,
L(t^3)
applying laplace transform we get
L(t^3) = 3! / (s^4)
so,
L[(t^3)e^(-2t)]
= 6 / (s+2)^4
Answer = 6/ (s+2)^4
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