Question

l want to solve this questions
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Answer 1

$ab {x}^{2} +{a}^{2}x + {b}^{2}x +ab \\ \\ \\ = ax(bx + a) + b(bx + a) \\ \\ \\ = (bx + a)(ax + b)$

The factorization of the given question is :-

$\boxed{\blue{\bold{(bx+a) (ax+b)}}}$

Now,

If we wish to get the value of x.

The given question should be a quadratic equation.

Hence,

It must be equated with zero to get the values for x.

Therefore,

$bx + a = 0 \\ \\ \\x = \frac{ - a}{b}$

$ax + b = 0 \\ \\ \\x = \frac{ - b}{a}$

$\rule{200}{2}$

$\rule{200}{2}$

Answer 2

Answer:

(ax+b)(bx+a)

Step-by-step explanation:

abx²+a²x+b²x+ab

=ax(bx+a)+b(bx+a)

=(bx+a)(ax+b)

=(ax+b)(bx+a)