Question

l will make the the brianlest answer if you explain with steps please do it urgently thanking you.
A particle covers 10m in the first 5s and 10m in next 3s .
Assuming constant acceleration. Find the initial speed,acceleration, and distance covered in next 2s??..???????........ thanking you please do urgently if you do it I make it Brian lest answer

Answer 1

Particle travels 10m in first 5 seconds

Using equation of motion S=ut+12at2

10=5u+25a2

Multiply both sides with 8

80=40u+100a ———————(1)

Particle travels 10m in next 3s (or) it travels 20m in first 8s
Again, using equation of motion S=ut+12at2

20=8u+64a2

Multiply both sides with 5

100=40u+160a ——————(2)

Subtract equation (2) from equation (1)

80−100=40u+100a−40u−160a

−20=−60a

a=13ms−2

Substitute value of a in equation (1)

80=40u+1003

40u=80−1003

40u=1403

u=76ms−1

We got acceleration = 13ms−2 and initial velocity (u) = 76ms−1

————————

Distance travelled in first 10s

S=ut+12at2

S=706+1026

S=1706m

Distance travelled in next 2s = Distance travelled in first 10s - Distance travelled in first 8s

= 1706m−20m

= 506m

= 8.3m

Hope it will help you my friend