l(x) =x2+3x find zero of polynomial
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Answered by
1
taking x common
x(x+3)=0
x=0,-3
x(x+3)=0
x=0,-3
Answered by
0
given that,
l(x)=x^2+3x
x(x+3)=0
now x=0 and x+3=0
and x=-3
therefore the roots of the quadratic equation 0,-3
l(x)=x^2+3x
x(x+3)=0
now x=0 and x+3=0
and x=-3
therefore the roots of the quadratic equation 0,-3
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