Question

l(x) =xsquare+2x+1

find the zeroes of the polynomial , with steps ​

Answer 1

Answer:

The value x of the given polynomial x^2+2x+1x

2

+2x+1 are -1 and -1.

Solution:

Given polynomial is expressed as

x^2+2x+1x

2

+2x+1

Factorizing the term x^2+2x+1x

2

+2x+1

we get,

\begin{gathered}\begin{array} { c } { x ^ { 2 } + 2 x + 1 = 0 } \\\\ { x ^ { 2 } + x + x + 1 = 0 } \\\\ { x ( x + 1 ) + 1 ( x + 1 ) = 0 } \\\\ { ( x + 1 ) ( x + 1 ) = 0 } \\\\ { x = - 1 \text { and } x = - 1 } \end{array}\end{gathered}

x

2

+2x+1=0

x

2

+x+x+1=0

x(x+1)+1(x+1)=0

(x+1)(x+1)=0

x=−1 and x=−1

∴ The zeroes of x^2+2x+1x

2

+2x+1 are -1 and -1.