Math, asked by gauriprad246, 4 days ago

l1,l2,l3lines are parallel and t1,t2 are two cheda bindu .l1,l2,l3 lines ku D,E,F three points cheda kare and DE= EF= CF=10cm and AD=4cm then EB=?​

Answers

Answered by madmax999
0

Answer:

Step-by-step explanation:

Correct option is B)

The straight lines L1,L2,L3 are parallel and lie in the same plane. A total number of m points are taken on L1. n points on L2 and k points on L3.  

Then maximum number of triangles formed with vertices at these points are= (Selecting 3 points from the m+n+k points to form a triangle)− [(m points lie on same line so selecting 3 points from this will not form a triangle) +(n points lie on same line so selecting 3 points from this will not form a triangle)+(k points lie on same line so selecting 3 points from this will not form a triangle)]

Number of Triangles= =  n+m+k C3-(nC3+mC3+kC3)

 

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