L2 +9L+ 14 = 0
please solve factorization
Answers
Answer:
=
−
2
=
−
7
Step-by-step explanation:
=
−
±
2
−
4
√
2
l=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
l=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
+
9
+
1
4
=
0
l^{2}+9l+14=0
l2+9l+14=0
=
1
a={\color{#c92786}{1}}
a=1
=
9
b={\color{#e8710a}{9}}
b=9
=
1
4
c={\color{#129eaf}{14}}
c=14
=
−
9
±
9
2
−
4
⋅
1
⋅
1
4
√
2
⋅
1
Step 2:
=
−
9
±
5
2
Step 3:
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.
=
−
9
+
5
2
=
−
9
−
5
2
Step 4:
Rearrange and isolate the variable to find each solution
=
−
2
=
−
7
(I don't know what's wrong with this :/)