l3-4xl>=9 find the domain and range
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Step-by-step explanation:
According to definition of absolute value:
|x| = x , if x ≥ 0 ("x" is positive or 0) and
|x| = - x , if x < 0 ("x" is negative)
1). Assume the value of expression (3 - 4x) is positive or zero, then
3 - 4x ≥ 9
- 4x ≥ 9 - 3 = 6
x ≤ 6 ÷ (- 4)
x ≤ - 1.5 , x ∈ (- ∞ , - 1.5]
2). Assume the value of expression (3 - 4x) is negative, then
- (3 - 4x) ≥ 9
3 - 4x ≤ - 9
- 4x ≤ - 12
x ≥ 3 , x ∈ [3 , ∞)
Thus, domain is ( - ∞, - 1.5] ∪ [3, ∞)
f(x) = |3 - 4x| - 9 ≥ 0
Thus, range is [0 , ∞)
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