LA. 23.9 cm
L.P.G. cylinder can withstand a pressure of 14.9
atmosphere. The pressure gauge of the cylinder indicates
12 atmosphere at 27°C. Due to a sudden fire in the
building the temperature rises. At what temperature will
the cylinder explode.
Ans. 99.5°C)
Answers
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Explanation:
P = 14.9 atm
V = 28 cm3
T = ?
P1 = 12 atm
V = V1
T1 = 300 K
Using gas equation,
PVT=P1V1T1
14.9×VT=12×V300
T = 372.5 K
T = 372.5 - 273 = 99.5 °C
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