La belongs to group 3 while Hg belongs
to group 12 and both belong to period 6
of the periodic table. Write down the
general outer electronic configuration of
the ten elements from La to Hg together
using orbital notation method.
Answers
Answer:
Explanation:
The ten elements starting from La (Lanthanum) to Hg (Mercury) across period 6 are :
Lanthanum (La), Haffnium (Hf), Tantalum (Ta), Tungsten (W), Rhenium (Re), Osmium (Os), Iridium (Ir), Platinum (Pt), Aurum (Au), and Mercury (Hg).
• Electron configuration of an element is the representation of its number of electrons in the form of s, p, d, and f orbitals.
• Also, number of electrons in a neutral atom = Atomic number of the element
• The electrons are filled according to the Afbau's principle.
• The electronic configuration of the aforementioned elements are as follows :
La (57) - [Xe] 5d1 6s2
Hf (72) - [Xe] 4f14 5d2 6s2
Ta (73) - [Xe] 4f14 5d3 6s2
W (74) - [Xe] 4f14 5d4 6s2
Re (75) - [Xe] 4f14 5d5 6s2
Os (76) - [Xe] 4f14 5d6 6s2
Ir (77) - [Xe] 4f14 5d7 6s2
Pt (78) - [Xe] 4f14 5d9 6s1
Au (79) - [Xe] 4f14 5d10 6s1
Hg (80) - [Xe] 4f14 5d10 6s2
[Xe] represents 54 number of electrons as the atomic number of Xe is 54. Therefore, for convenience, 54 electrons are represented as [Xe].