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25. You are given two converging lens of focal lengths 1.25 cm and 5 cm to design a compound microscope,
If it is desired to have a magnification of 30, find out the separation between the objective and the
eyepiece.
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Answer:
Given $f_{ o }$ = 1.25 cm $f_{e }$ = -5 cm
Magnification, m= 30,
D= 25 cm
If the object is very close to the principal focus of the objective and the image formed by the objective is very close to eyepiece, then magnifying power of a microscope is given by
m = -L/$f_{ o }$ .D/ $f_{ e ]$ =
30 = L/1.25. 25/5
===> L = 125x30x5/25x100
> L = 25 x 30/100
>L 30/4
===> L = 7.5 cm
This is a required separation between the objective and the eyepiece.
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