label the digram it is urgent my paper can start anytime
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Explanation:
Let the first volume of water be V1. Let the second volume of water be V2. Let the initial temperature of the first volume of water be θ1. Let the initial temperature of the second volume of water be θ2.
Let the energy required to heat a unit volume of water by unit temperature by C.
So, if the final temperature is θfinal, we have
heat gained by the first volume of water
=V
1
×C×(θ
final
−θ
1
)
and
heat lost by the second volume of water
=V
2
×C×(θ
2
−θ
final
).
By the law of conservation of energy,
heat lost = heat gained
∴V
1
×C×(θ
final
−θ
1
)=V
2
×C×(θ
2
−θ
final
)
∴V
1
θ
final
−V
1
θ
1
=V
2
θ
2
−V
2
θ
final
∴θ
final
=V
1
θ
1
+V
2
θ
2
V
1
+V
2
Substituting the given values,
θ
final
=
2
30+50
=40
∘
C.
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