Question

LADC = 135° LDQO= 40°
Find LABC
Find LDAB
Find LDCB
Find LBPC



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Answer 1

Answer:

Given ADC = 135°

DQC = 40°

To find ABC

DAB

DCB

BPC

Solution: ADC+CDQ = 180 (Straight angle)

135 + CDQ = 180

CDQ = 45°

Now, in triangle DCQ

DCQ+DQC+QCD = 180° (Angle sum property)

DCQ + 40 + 45 = 180°

DCQ = 95°

DCQ+DCB = 180° (Straight angle)

95+ DCB = 180°

DCB = 85°

hence ABCD is a cyclic quadrilateral

DAB+ DCB = 180°

DAB + 85 = 180°

DAB = 95°

and ABC + ADC = 180°

ABC + 135 = 180°

ABC = 45°

Now, in triangle BCP

BPC + PCB + PBC = 180°

BPC + 85 + 45 = 180

BPC + 130 = 180

BPC = 50°

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Answer 2

Step-by-step explanation:

Hope u will understand..