Ladder is 15 feet long, leaning against the building. The base of the ladder is 9 feet away from the building. Explain the minimum and maximum height can we reach by using the ladder. The distance between the ladder and building should not be more than 12 feet.
Answers
Answer:
Step-by-step explanation:This is simple Pythagorean math.
15 X 15=225 (vertical heigth)
9 X 9 = 81 ( base)
225 + 81 = 306 ( length of slope)
The square root of 306 is the length of the ladder
17 1/2 feet to reach 15′ up the wall.
Written as a2 + b2 = c2
Only works with right triangles.
Oops, I got the idea wrong. So the ladder is 15′ long. Still simple math.
This time the ladder is “c2” 15 X 15 =225
9 feet out is still squared to 81.
So c2 (225) - b2 (81) is 144 (a2)
Sqrt of 144 is 12. The ladder will be 12′ up the wall. However you cannot stand on the top 2 rungs because there is no room for your toes. Therefore you effectively have a 10′ ladder.
But wait t here is more. You don’t need the base to be 9′. That is too much. The ladder will slip out from under you. Do the math and see what you can reach if you set the base at 4′ out.
Answer:
Minimum height reached by ladder = 9 Feet
Data not enough to calculate max height reached by ladder
Step-by-step explanation:
Ladder is 15 feet long
Base of ladder is 9 feet away
Height of building where ladder will reach = H
Using Pythagoras theorem
15² = 9² + H²
=> H² = 225 - 81
=> H² = 144
=> H = 12
Currently height can be reached = 12 Feet
Max distance between the ladder = 12 feet.
in That case height ladder will go
H² = 15² - 12²
=> H² = 225 - 144
=> H² = 81
=> H = 9 feet
9 feet is the minimum height
Maximum height will depend upon minimum distance between ladder & building which is not mentioned
if that is taken as Zero then Maximum height ladder will go = 15 feet