Question

ladder is placed against a wall such that its foot is at distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. The length of the ladder is

Answer 1

Answer:

Hey buddy here your anwer..

Step-by-step explanation:

Let AB be the ladder and CA be the wall with the window at A

BC = 2.5 m

CA = 6 m

From Pythagoras theorem , We Have :

AB^2 = BC^2 + CA^2

= (2.5)^2 + (6)^2

= 42.25

So , AB = 6.5

Thus , the length of the ladder is 6.5 m

Answer 2

↦Solution : -

REFER TO THE ATTACHMENT

Let AB be the ladder and CA be the wall with the window at A.... Also ,

BC = 2.5m and CA = 6m

From Pythagoras Theorem , we have : -

AB² = BC² + CA²

(2.5)² + (6)²

42.25

AB = 6.5

So , the length of ladder is 6.5m ..