ladder length is 15m reaches window 9m above the ground find distance between the base of wall
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Answered by
2
Hola there,
Length of ladder = 15 m
Distance between the ground and window = 9 m
So,
distance between the ground and the base of wall = √(15)² - (9)²
= √225 - 81
= √144
= 12 m. .... Ans
Hope this helps....:)
Length of ladder = 15 m
Distance between the ground and window = 9 m
So,
distance between the ground and the base of wall = √(15)² - (9)²
= √225 - 81
= √144
= 12 m. .... Ans
Hope this helps....:)
Answered by
0
Hi!
Here is the answer to your question.
The given situation can be represented as,
Let the distance of the foot of the ladder from the wall be a m. I.e., BC = a m
Applying Pythagoras Theorem,
BC^2 + AB^2 = AC^2 (Pythagoras Theorem)
⇒ a^2 + (12)^2 = (15 m)2^
⇒ a^2 = 225 – 144
⇒ a^2 = 81
⇒ a = 9
Thus, the distance of the foot of the ladder from the wall is 9 m.
Here is the answer to your question.
The given situation can be represented as,
Let the distance of the foot of the ladder from the wall be a m. I.e., BC = a m
Applying Pythagoras Theorem,
BC^2 + AB^2 = AC^2 (Pythagoras Theorem)
⇒ a^2 + (12)^2 = (15 m)2^
⇒ a^2 = 225 – 144
⇒ a^2 = 81
⇒ a = 9
Thus, the distance of the foot of the ladder from the wall is 9 m.
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