Question

Lag2base10=0.3010 the value of log5base10 is

Answer 1

log(2) = 0.3010 
log(1/2) = log(1) - log(2) = 0 - 0.301
log(0.5) = - 0.301
log(5) = log(0.5*10) = log(0.5) + log(10) = 0.699

Answer 2

$Log_{10} 10 = 1\\\\Log_{10} (5 *2) = 1\\\\Log_{10} 5+Log_{10} 2=1\\\\Log_{10} 5=1-0.3010 = 0.6990$