Question

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Answer 1

the height of the two trees AB and CD be b and a respectively. Distance between the trees BC = p Let EF = h be the height of point of intersection of the lines joining the top of each tree to the foot of the opposite trees. Let CF = x then BF = (p – x) In Δ’s ABC�and EFC, ∠ABC = ∠EFC = 90° ∠C = ∠C (common angle) ∴ ΔABC ~ ΔEFC (By AA similarity theorem) Similarly, ΔDCB ~ ΔEFB (By AA similarity theorem)

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